Write the equation of excess pressure for liquid drop.
Pressure inside two soap bubbles are $1.01$ and $1.02$ atmosphere, respectively. The ratio of their volumes is
Two narrow bores of diameter $5.0\, {mm}$ and $8.0\, {mm}$ are joined together to form a $U-$shaped tube open at both ends. If this ${U}$-tube contains water, what is the difference in the level of two limbs of the tube.
[Take surface tension of water ${T}=7.3 \times 10^{-2} \, {Nm}^{-1}$, angle of contact $=0, {g}=10\, {ms}^{-2}$ and density of water $\left.=1.0 \times 10^{3} \,{kg} \,{m}^{-3}\right]$ (in $mm$)
A soap bubble assumes a spherical surface. Which of the following statement is wrong
What is the pressure inside the drop of mercury of radius $3.00 \;mm$ at room temperature? Surface tension of mercury at that temperature $\left(20\,^{\circ} C \right)$ is $4.65 \times 10^{-1}\; N m ^{-1} .$ The atmospheric pressure is $1.01 \times 10^{5}\; Pa$. Also give the excess pressure inside the drop.
A capillary type tube $AB$ is connected to a manometer $M$ as shown in the figure. Stopper $S$ controls the flow of air. $AB$ is dipped into a soap solution where surface tension is $T$ . On opening the stopper for a while, a bubble is formed at $B$ end of the manometer and the level difference in manometer limbs is $h$ . If $P$ is the density of manometer soap solution and $r$ the radius of curvature of bubble, then the surface tension $T$ of the liquid is given by ...